Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 592: 72

Answer

$x=1.365$

Work Step by Step

$5^x=9$ We then find: $log5^x=log9$ We use log rules to have: $xlog5=log9$ $x=1.365$
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