#### Answer

$x=-6$ and $x=2$

#### Work Step by Step

We are given the equation $x^{2}+4x=12$. Subtract 12 from both sides to get all terms on one side.
$x^{2}+4x-12=0$
We know that -2 and 6 are factors of 12 and the sum of -2 and 6 is 4, which is the coefficient on the middle term.
Therefore, the equation can be factored into the form $(x-2)(x+6)$.
Set both terms equal to 0
$x-2=0$
Add 2 to both sides.
$x=2$
$x+6=0$
Subtract 6 from both sides.
$x=-6$