Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.7 - Common Logarithms, Natural Logarithms, and Change of Base - Exercise Set - Page 586: 68



Work Step by Step

We are given the equation $2x+3=5-2(3x-1)$. We can use the distributive property to simplify. $2x+3=5-2(3x-1)=5-2(3x)-2(-1)=5-6x+2$ Combine like terms on the right side. $2x+3=-6x+7$ Subtract 3 from both sides. $2x=-6x+4$ Add 6x to both sides. $8x=4$ Divide both sides by 8. $x=\frac{4}{8}=\frac{1}{2}$
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