Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.6 - Properties of Logarithms - Exercise Set: 80


Because $log_{b}1=0$

Work Step by Step

We are given that $log_{b}7=log_{b}(\frac{7}{1})=log_{b}7-log_{b}1$. Although this seems counterintuitive, we know that $log_{b}7=log_{b}7-log_{b}1$, because $log_{b}1=0$ according to the properties of logarithms. Therefore, $log_{b}7=log_{b}7-log_{b}1=log_{b}7-0=log_{b}7$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.