Answer
Because $log_{b}1=0$
Work Step by Step
We are given that $log_{b}8=log_{b}(8\times1)=log_{b}8+log_{b}1$.
Although this seems counterintuitive, we know that $log_{b}8=log_{b}8+log_{b}1$, because $log_{b}1=0$ according to the properties of logarithms.
Therefore, $log_{b}8=log_{b}8+log_{b}1=log_{b}8+0=log_{b}8$.
