Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set - Page 572: 91



Work Step by Step

We are given $\frac{3x}{x+3}+\frac{9}{x+3}$. Both denominators are the same, so we can combine the numerators over the common denominator. $\frac{3x}{x+3}+\frac{9}{x+3}=\frac{3x+9}{x+3}=\frac{3(x+3)}{x+3}=3$
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