Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.5 - Logarithmic Functions - Exercise Set - Page 572: 87



Work Step by Step

Factoring the given expressions and cancelling the common factors between the numerator and the denominator, the given rational expression, $ \dfrac{x^2-8x+16}{2x-8} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{(x-4)(x-4)}{2(x-4)} \\\\= \dfrac{(\cancel{x-4})(x-4)}{2(\cancel{x-4})} \\\\= \dfrac{x-4}{2} .\end{array}
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