# Chapter 9 - Review: 16b

-1

#### Work Step by Step

We are given that $f(x)=\sqrt(x+2)$ is a one-to-one function. Also we know that the inverse of a one-to-one function $f$ is the one-to-one function $f^{-1}$ that consists of the set of all ordered pairs $(y,x)$ where $(x,y)$ belongs to $f$. From 16a, we know that $f(-1)=1$, which means that $f$ consists of the ordered pair $(-1,1)$. Therefore, (1,-1) must be a part of $f^{-1}$. Therefore, $f^{-1}(1)=-1$.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.