Answer
$2x^{2}-9x-5$
Work Step by Step
We are given that $f(x)=x-5$ and $g(x)=2x+1$.
We know that $(f\times g)(x)=f(x)\times g(x)$.
Therefore, $(f\times g)(x)=f(x)\times g(x)=(x-5)(2x+1)$.
We can use the FOIL method to simplify.
F=$(x\times2x)=2x^{2}$
O=$(x\times1)=x$
I=$(-5\times2x)=-10x$
L=$(-5\times1)=-5$
Next, we can add these terms together.
$(2x^{2})+(x)+(-10x)+(-5)=2x^{2}-9x-5$
