Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 8 - Section 8.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 527: 59

Answer

30 and 30

Work Step by Step

The two numbers are $x$ and $60-x$. The product is $(x)(60-x)$, and we want this to be as large as possible. This product is as large as possible as the vertex. $x*(60-x)$ $60x-x^2$ $y=-x^2+60x$ $a=-1$, $b=60$, $c=0$ Vertex: $x=-b/2a$ $x=-60/2*-1$ $x=-60/-2$ $x=30$ $x*(60-x)$ $30*(60-30)$ $30*30$ $900$ 30 and 30
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