Answer
180 calendars
Work Step by Step
$P(x)=360x-x^2$
$P(x)=-x^2+360x$
Since the graph opens downward, the vertex will have the highest point on the graph.
$a=-1$, $b=360$, $c=0$
Vertex: $x=-b/2a$
$x=-360/2*-1$
$x=-360/-2$
$x=180$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 8 - Section 8.6 - Further Graphing of Quadratic Functions - Exercise Set - Page 527: 58a
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