Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents - Page 447: 38

Answer

$\dfrac{7}{\sqrt[]{21}}$

Work Step by Step

Multiplying both the numerator and the denominator by $ 7 $, then the rationalized-numerator form of the given expression, $ \sqrt[]{\dfrac{7}{3}} ,$ is \begin{array}{l}\require{cancel} \sqrt[]{\dfrac{7}{3}\cdot\dfrac{7}{7}} \\\\= \sqrt[]{\dfrac{(7)^2}{21}} \\\\= \dfrac{\sqrt[]{(7)^2}}{\sqrt[]{21}} \\\\= \dfrac{7}{\sqrt[]{21}} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.