Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Sections 7.1-7.5 - Integrated Review - Radicals and Rational Exponents: 29


$2\sqrt 5-5\sqrt 3+5\sqrt 7$

Work Step by Step

$\sqrt 20-\sqrt 75+5\sqrt 7=\sqrt (4\times5)-\sqrt (25\times3)+5\sqrt 7=(\sqrt 4\times\sqrt 5)-(\sqrt 25\times\sqrt3)+5\sqrt 7=2\sqrt 5-5\sqrt 3+5\sqrt 7$ We know that $\sqrt 4=2$, because $2^{2}=4$. We know that $\sqrt 25=5$, because $5^{2}=15$.
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