Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set - Page 456: 94

$2,744 \text{ deliveries per day}$

Using the given function, $ C(x)=80\sqrt[3]{x}+500 ,$ then the cost, $C(x),$ is below $\$1,620$ when \begin{array}{l}\require{cancel} 80\sqrt[3]{x}+500<1620 .\end{array} Using the properties of inequality, the inequality above is equivalent to \begin{array}{l}\require{cancel} 80\sqrt[3]{x}<1620-500 \\ 80\sqrt[3]{x}<1120 \\ \sqrt[3]{x}