Answer
-6
Work Step by Step
$\sqrt 36=6$, because $(6)^{2}=(6\times6)=36$
By adding a negative sign in front of $\sqrt 36$, we are taking the negative of $\sqrt 36$, which is $-(6)=-6$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set - Page 416: 7
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