Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.1 - Radicals and Radical Functions - Exercise Set: 22



Work Step by Step

$\sqrt[3] \frac{27}{64}=\frac{3}{4}$, because $(\frac{3}{4})^{3}=\frac{3}{4}\times\frac{3}{4}\times\frac{3}{4}=\frac{9}{16}\times\frac{3}{4}=\frac{27}{64}$
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