Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.5 - Solving Equations Containing Rational Expressions - Exercise Set - Page 379: 64

Answer

$x=\left\{ -\dfrac{1}{4},\dfrac{1}{9}, \right\}$

Work Step by Step

Using $x^{-a}=\dfrac{1}{x^a}$, the given equation, $ x^{-2}-5x^{-1}-36=0 ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{1}{x^2}-\dfrac{5}{x}-36=0 .\end{array} Multiplying both sides by the $LCD= x^2 ,$ then the solution to the given equation is \begin{array}{l}\require{cancel} 1(1)-x(5)-x^2(36)=0 \\\\ 1-5x-36x^2=0 \\\\ -36x^2-5x+1=0 \\\\ 36x^2+5x-1=0 \\\\ (9x-1)(4x+1)=0 \\\\ x=\left\{ -\dfrac{1}{4},\dfrac{1}{9}, \right\} .\end{array}
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