Answer
$\dfrac{15}{17}$
Work Step by Step
Simplify the numerator and the denominator to have;
$=\dfrac{\frac{14}{7} + \frac{1}{7}}{\frac{21}{7} - \frac{4}{7}}
\\=\dfrac{\frac{15}{7}}{\frac{17}{7}}$
RECALL:
$\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \cdot \dfrac{d}{c}$
Use the rule above to have:
$\\=\dfrac{15}{7} \cdot \dfrac{7}{17}$
Cancel the common factors to have:
$\require{cancel}
\\=\dfrac{15}{\cancel{7}} \cdot \dfrac{\cancel{7}}{17}
\\=\dfrac{15}{17}$
