Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.3 - Simplifying Complex Fractions - Exercise Set - Page 360: 1

Answer

$4$

Work Step by Step

RECALL: $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \cdot \dfrac{d}{c}$ Use the rule above to have: $\\=\dfrac{10}{3x} \cdot \dfrac{6x}{5}$ Cancel the common factors to have: $\require{cancel} \\=\dfrac{\cancel{10}2}{\cancel{3x}} \cdot \dfrac{\cancel{6x}2}{\cancel{5}} \\=4$
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