#### Answer

$4+x^{2}$

#### Work Step by Step

The distributive property holds that $a(b+c)=ab+ac$ for real numbers a, b, and c.
Therefore, $x^{2}(\frac{4}{x^{2}}+1)=(x^{2}\times\frac{4}{x^{2}})+(x^{2}\times1)=4+x^{2}$

Published by
Pearson

ISBN 10:
0321785045

ISBN 13:
978-0-32178-504-6

$4+x^{2}$

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