Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.2 - Adding and Subtracting Rational Expressions - Exercise Set - Page 355: 90

Answer

3

Work Step by Step

We know that $\sqrt[3] 27=3$, because $3^{3}=3\times3\times3=27$.
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