Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set - Page 346: 72

Answer

$f(-5)=\dfrac{7}{10}$ $f(0)=\dfrac{2}{5}$ $f(10)=\dfrac{8}{5}$

Work Step by Step

To find $f(-5), f(0), \text{ and } f(10)$, susbtitute -5, 0, and 10, respectively, to $x$ to have: $f(-5)=\dfrac{-5-2}{-5+(-5)}=\dfrac{-7}{-10}=\dfrac{7}{10} \\ \\f(0)=\dfrac{0-2}{-5+0}=\dfrac{-2}{-5}=\dfrac{2}{5} \\ \\f(10)=\dfrac{10-2}{-5+10}=\dfrac{8}{5}$
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