Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set - Page 346: 62



Work Step by Step

$\dfrac{m^{3}-n^{3}}{m-n}$ The numerator is a difference of cubes. Factor it: $\dfrac{m^{3}-n^{3}}{m-n}=\dfrac{(m-n)(m^{2}+mn+n^{2})}{m-n}=...$ Simplify by removing the factors that appear both in the numerator and in the denominator of the resulting expression: $...=m^{2}+mn+n^{2}$
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