# Chapter 6 - Section 6.1 - Rational Functions and Multiplying and Dividing Rational Expressions - Exercise Set: 62

$\dfrac{m^{3}-n^{3}}{m-n}=m^{2}+mn+n^{2}$

#### Work Step by Step

$\dfrac{m^{3}-n^{3}}{m-n}$ The numerator is a difference of cubes. Factor it: $\dfrac{m^{3}-n^{3}}{m-n}=\dfrac{(m-n)(m^{2}+mn+n^{2})}{m-n}=...$ Simplify by removing the factors that appear both in the numerator and in the denominator of the resulting expression: $...=m^{2}+mn+n^{2}$

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