Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Test - Page 333: 29d

Answer

When $$t=11sec$$

Work Step by Step

We have $$h(t) = -16t^2+96t+880 = -16(t-11)(t+5)$$ When hit the ground the position will be $0ft$, so $$-16(t-11)(t+5) = 0$$ Solving the parenthesis 1)$$t-11=0$$ $$t=11$$ 2)$$t+5=0$$ $$t=-5$$ As time can not be negative then $$t=11sec$$
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