## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 5 - Test - Page 333: 29c

#### Answer

$-16(t+5)(t-11)$

#### Work Step by Step

$-16t^{2}+96t+880$ Factor out the GCF, $-16$. $-16(t^{2}-6t-55)$ In this trinomial, $(t^{2}-6t-55),$ $a=1$, $b=-6$ and $c=-55$. Splitting the middle term $b$ into two numbers $-11$ and $5$, whose product is $-55$ $(a \times c)$ and whose sum is $(b)$, $-6$. $-16(t^{2}-11t+5t-55)$ Factor out by grouping. $-16((t^{2}-11t)+(5t-55))$ $-16(t(t-11)+5(t-11))$ $-16(t+5)(t-11)$

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