Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 310: 8

Answer

$4x^3-13x^2-5x+2$

Work Step by Step

Using the Distributive Property, the given expression simplifies to \begin{array}{l} (4x-1)(x^2-3x-2) \\= 4x(x^2)+4x(-3x)+4x(-2)-1(x^2)-1(-3x)-1(-2) \\= 4x^3-12x^2-8x-x^2+3x+2 \\= 4x^3+(-12x^2-x^2)+(-8x+3x)+2 \\= 4x^3-13x^2-5x+2 .\end{array}
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