Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Sections 5.1-5.7 - Integrated Review - Operations on Polynomials and Factoring Strategies - Page 310: 1

Answer

$2y^2+2y-11$

Work Step by Step

The given expression simplifies to \begin{array}{l} (-y^2+6y-1)+(3y^2-4y-10) \\= (-y^2+3y^2)+(6y-4y)+(-1-10) \\= 2y^2+2y-11 .\end{array}
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