Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 294: 8

Answer

$3y^2z^3$

Work Step by Step

\begin{align*} \text{The $GCF$ of $ 12, 9, \text{ and } 15 \text{ is } 3 $} .\\\\ \text{The $GCF$ of $ y^2, y^3, \text{ and } y^2 \text{ is } y^2 $} .\\\\ \text{The $GCF$ of $ z^4, z^4, \text{ and } z^3 \text{ is } z^3 $} .\end{align*} Hence, the $GCF$ of the given expressions is $3y^2z^3$.
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