Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Section 5.5 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 294: 3

Answer

$y^2z^2$

Work Step by Step

\begin{align*} \text{The $GCF$ of $ y^3, y^2, \text{ and } y^2 \text{ is } y^2 $} .\\\\ \text{The $GCF$ of $ z^3, z^3, \text{ and } z^2 \text{ is } z^2 $} .\end{align*} Hence, the $GCF$ of the given expressions is $y^2z^2$.
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