Answer
approximately $\$11607.55$
Work Step by Step
Using $A=P\left( 1+\dfrac{r}{n}\right)^{nt}$ or the Compound Interest Formula, then with $P=10,000,$ $r=0.05,$ $n=4$, and $t=3,$ the amount of money, $A,$ after $3$ years is
\begin{array}{l}\require{cancel}
A=10000\left( 1+\dfrac{0.05}{4}\right)^{4(3)}
\\
A=10000\left( 1.0125\right)^{12}
\\
A=11607.545177229987146472703898326
\\
A\approx11607.55
.\end{array}
Hence, the amount after $3$ years is $\text{
approximately $\$11607.55$
.}$
