## Intermediate Algebra (6th Edition)

$x=-4 \text{ or } x =4$
Subtract 8 to both sides to have: $\\8+|4c|-8 = 24-8 \\|4c|=16$ RECALL: $\\|a| = a \text{ if} a \ge 0 \\|a| = -a \text{ if } a \lt 0$ Use this definition to have: $\\4c = 16 \text{ or } 4c = -16 \\c=4 \text{ or } c = -4$