Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 5 - Cumulative Review: 12

Answer

$x=-4 \text{ or } x =4$

Work Step by Step

Subtract 8 to both sides to have: $\\8+|4c|-8 = 24-8 \\|4c|=16$ RECALL: $\\|a| = a \text{ if} a \ge 0 \\|a| = -a \text{ if } a \lt 0$ Use this definition to have: $\\4c = 16 \text{ or } 4c = -16 \\c=4 \text{ or } c = -4$
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