Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 233: 45

Answer

$x°=60°$ $y°=55°$ $z°=65°$

Work Step by Step

The sum of the interior angles of a triangle is $180°$ $x°+y°+z°=180°$ Equation $(1)$ An exterior angle of a triangle is equal to the sum of its interior opposite angles. So, From figure, $2x°-5°=x°+y°$ $2x°-5°-x°=y°$ $y°=x°-5°$ Equation $(2)$ $2x°+5°=x°+z°$ $2x°+5°-x°=z°$ $z°=x°+5°$ Equation $(3)$ Substituting $y°$ and $z°$ in Equation $(1)$, we get, $x°+y°+z°=180°$ $x°+x°-5°+x°+5°=180°$ $3x°=180°$ $x°=60°$ Substituting $x°$ in Equation $(2)$ and in Equation $(3)$, $y°=x°-5°$ $y°=60°-5°$ $y°=55°$ $z°=60°+5°$ $z°=65°$
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