Answer
No. of Free Throws : $201$
No. of two point field goals : $140$
No. of three point field goals :$88$
Work Step by Step
Let No. of free (one point) throws be $x$
No. of two point field goals be $y$
No. of three point field goals be $z$
Given,
Total points $=745$
$x+2(y)+3(z)= 745$
$x+2y+3z=745$ Equation $(1)$
No. of two point field goals $=36$ fewer than two times the No. of three point field goals.
$y=2z-36$ Equation $(2)$
No. of free throws $= 61$ more than the No. of two point field goals.
$x=y+61$ Equation $(3)$
From Equation $(2)$ and Equation $(3)$
$x=y+61$
$x=2z-36+61$
$x=2z+25$
$x+2y+3z=745$
$2z+25+2(2z-36)+3z=745$
$2z+25+4z-72+3z=745$
$9z-47=745$
$9z=792$
$z=88$
Substituting $z$ value in Equation $(2)$
$y=2z-36$
$y=2(88)-36$
$y=176-36$
$y=140$
Substituting $y$ value in Equation $(3)$
$x=y+61$
$x=140+61$
$x=201$
No. of Free Throws : $201$
No. of two point field goals : $140$
No. of three point field goals :$88$
