Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 232: 26

Answer

A template costs 1.90, a pad of paper costs 2.25, and a pencil costs .75.

Work Step by Step

We first use equations to model the situation: $3t+p = 6.45$ $ 2a + 4p = 7.50$ $a = 3p$ Note, a stands for the price of a pad of paper. We substitute the third equation into the second equation to find: $ 2(3p) + 4p = 7.50$ Now, we use PEMDAS, a method for simplification. This acronym reminds us that we must first address parentheses, and then exponents. Next, we address multiplication and division, going from left to right. Lastly, we simplify addition and subtraction from left to right. This gives: $ p =.75$ We substitute this result into the third equation to find: $ a = 3(.75) = 2.25$ We now find: $t = 1.90$
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