Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.3 - Systems of Linear Equations and Problem Solving - Exercise Set - Page 230: 5

Answer

The speed of the plane in still air is $520$ miles per hour and the speed of the wind is $40$ miles per hour.

Work Step by Step

The plane traveled $2520$ miles with the wind in $4.5$ hours and $2160$ miles against the wind in the same amount of time. Speed of the plane with the wind: $\frac{2520}{4.5} = 560$ miles per hour Speed of the plane against the wind: $\frac{2160}{4.5} = 480$ miles per hour Let $p$ be the speed of the plane in still air in miles per hour and let $w$ be the speed of the wind in miles per hour. $p + w = 560$ Equation $(1)$ $p - w = 480$ Equation $(2)$ Equation $(1)$ + Equation $(2)$ $2p = 1040$ $p=520$ Substitute $p$ into Equation $(1)$. $520 + w = 560$ $w=40$ The speed of the plane in still air is $520$ miles per hour and the speed of the wind is $40$ miles per hour.
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