Answer
Thus, the first number is 10, and the second number is 8.
Work Step by Step
We set up a system of equations using the provided information:
$x = 2+y$
and
$2x = 3y-4$
where x is the first number and y is the second number.
We substitute:
$2(2+y)=3y-4$
$4+2y=3y-4$
$y=8$
We now find the first number:
$x=y+2=8+2=10$
Thus, the first number is 10, and the second number is 8.
