Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations in Three Variables - Exercise Set - Page 221: 36

Answer

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Work Step by Step

We know that the given equations must satisfy the initial condition. Thus, we find an equation which makes the first statement true, starting with: $$x+y=z$$ This will not be a true statement, so we multiply x by two to find an equation that will work: $$2x+y=z....(1)$$ We now find another equation that satisfies the equation. We know that x is twice as great as y, so we find: $$ 2y = x...(2)$$ We now find a third equation. Since z is 5 times as great as y, we can write: $$5y=z...(3)$$
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