Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations in Three Variables - Exercise Set - Page 221: 33

Answer

$y = \frac{-5}{3}$

Work Step by Step

$-y -5(y+5) = 3y-10$ $-y-5y-25 = 3y-10$ $-6y-25 = 3y-10$ $-6y-3y = 25-10$ $-9y= 15$ $y= \frac{15}{-9}$ $y=-\frac{5}{3}$
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