Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations in Three Variables - Exercise Set - Page 220: 17

Answer

No Solution.

Work Step by Step

$x+2y-z=5$ Equation $(1)$ $6x+y+z=7$ Equation $(2)$ $2x+4y-2z=5$ Equation $(3)$ Add Equation $(1)$ and Equation $(2)$ $x+2y-z+6x+y+z=5+7$ $7x+3y=12$ Equation $(4)$ Multiply Equation $(2)$ by $2$ and add with Equation $(3)$ $2(6x+y+z)+2x+4y-2z=2(7)+5$ $12x+2y+2z+2x+4y-2z=14+5$ $14x+6y=19$ Equation $(5)$ Multiply Equation $(4)$ by $-2$ and add with Equation $(5)$ $-2(7x+3y)+14x+6y=-2(12)+19$ $-14x-6y+14x+6y=-24+19$ $0=-5$ Since this statement is not true, the equations are parallel and have no solution.
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