Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations in Three Variables - Exercise Set - Page 220: 14

Answer

$(-4,5,-20)$

Work Step by Step

$x+2y=6$ Equation $(1)$ $7x+3y+z=-33$ Equation $(2)$ $x-z=16$ Equation $(3)$ Add Equation $(2)$ and Equation $(3)$ $7x+3y+z+x-z=-33+16$ Combine like terms. $8x+3y = -17$ Equation $(4)$ Multiply Equation $(1)$ by $-8$ and add with Equation $(4)$ $-8(x+2y)+8x+3y=-8(6)-17$ $-8x-16y+8x+3y=-48-17$ $-13y=-65$ $13y=65$ $y=5$ Substitute $y=5$ in Equation $(1)$ to get $x$ $x+2y=6$ $x+2(5)=6$ $x+10=6$ $x=6-10$ $x=-4$ Substitute $x$ value in Equation $(3)$ to get $z$ $x-z=16$ $-4-z=16$ $-z=16+4$ $-z=20$ $z= -20$ Solution: $(-4,5,-20)$
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