Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 249: 10

Answer

$(-1,2,0)$

Work Step by Step

Given Equations $5x+7y=9$ Equation $(1)$ $14y-z=28$ Equation $(2)$ $4x+2z=-4$ Equation $(3)$ From Equation $(2)$ $14y-z=28$ $14y-28=z$ $z=14y-28$ Substituting $z=14y-28$ in Equation $(3)$ $4x+2z=-4$ $4x+2(14y-28)=-4$ $4x+28y-56=-4$ $4x+28y=-4+56$ $4x+28y=52$ $4(x+7y)=52$ $x+7y=13$ Equation $(4)$ Subtracting Equation $(4)$ From Equation $(1)$ $5x+7y-(x+7y)=9-13$ $5x+7y-x-7y=-4$ $4x=-4$ $x=-1$ Substituting $x$ value in Equation $(1)$ $5x+7y=9$ $5(-1)+7y=9$ $-5+7y=9$ $7y=9+5$ $7y=14$ $y=2$ Substituting $x$ value in Equation $(3)$ $4x+2z=-4$ $4(-1)+2z=-4$ $-4+2z=-4$ $2z=-4+4$ $2z=0$ $z=0$ Solution: $(-1,2,0)$
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