Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 4 - Review - Page 249: 1

Answer

$(-3, 1)$ Please see the graph.

Work Step by Step

$3x+10y=1$ $x+2y=-1$ Elimination $(x+2y)*-3=-1*-3$ $-3x-6y=3$ $3x+10y+(-3x-6y)=1+3$ $3x+10y-3x-6y=4$ $4y=4$ $4y/4=4/4$ $y=1$ $x+2y=-1$ $x+2(1)=-1$ $x+2=-1$ $x+2-2=-1-2$ $x=-3$ $3x+10y=1$ $x+2y=-1$ Substitution $x+2y=-1$ $x+2y-2y=-1-2y$ $x=-1-2y$ $3x+10y=1$ $3(-1-2y)+10y=1$ $-3-6y+10y=1$ $-3+4y=1$ $-3+4y+3=1+3$ $4y=4$ $4y/4=4/4$ $y=1$ $x+2y=-1$ $x+2(1)=-1$ $x+2=-1$ $x+2-2=-1-2$ $x=-3$
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