Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 18



Work Step by Step

The given line has a slope of $\frac{2}{3}$ and goes through the point (-9,4). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=\frac{2}{3}$ and $(x_{1},y_{1})=(-9,4)$. $y-4=\frac{2}{3}(x+9)=\frac{2}{3}x+6$ Add 4 to both sides. $y=\frac{2}{3}x+10$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.