Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set: 15



Work Step by Step

The given line has a slope of -2 and goes through the point (1,-3). We can write this line in point-slope form $y-y_{1}=m(x-x_{1})$ with $m=-2$ and $(x_{1},y_{1})=(1,-3)$. $y+3=-2(x-1)=-2x+2$ Subtract 3 from both sides. $y=-2x-1$ This line is now in the slope-intercept form of $y=mx+b$.
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