## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 3 - Section 3.3 - Graphing Linear Functions - Exercise Set - Page 150: 33

See graph

#### Work Step by Step

$3x+5y=7$ Find the x-intercept by substituting 0 for y. $3x=7$ $x=\frac{7}{3}$ $(\frac{7}{3},0)$ Find the y-intercept by substituting 0 for x. $5y=7$ $y=\frac{7}{5}$ $(0,\frac{7}{5})$ Plot these points and connect with a straightedge.

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