Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 3 - Section 3.3 - Graphing Linear Functions - Exercise Set - Page 150: 13

Answer

See graph
1485231075

Work Step by Step

$x-y=3$ $y=x-3$ To find the x-intercept, substitute 0 for y. $0=x-3$ $x=3$ $(3,0)$ To find the y-intercept, substitute 0 for x. $y=0-3$ $y=-3$ $(0,-3)$ Plot these points and connect with a straightedge. $f(x)=x-3$
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