## Intermediate Algebra (6th Edition)

$x-y=3$ $y=x-3$ To find the x-intercept, substitute 0 for y. $0=x-3$ $x=3$ $(3,0)$ To find the y-intercept, substitute 0 for x. $y=0-3$ $y=-3$ $(0,-3)$ Plot these points and connect with a straightedge. $f(x)=x-3$