## Intermediate Algebra (6th Edition)

$C=\dfrac{5(F-32)}{9}$
Using the properties of equality, in terms of $C$, the given expression, $F=\dfrac{9}{5}C+32 ,$ is equivalent to \begin{array}{l}\require{cancel} F-32=\dfrac{9}{5}C \\\\ 5(F-32)=9C \\\\ \dfrac{5(F-32)}{9}=C \\\\ C=\dfrac{5(F-32)}{9} .\end{array}