Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Test: 13


$C=\dfrac{5(F-32)}{9} $

Work Step by Step

Using the properties of equality, in terms of $C$, the given expression, $ F=\dfrac{9}{5}C+32 ,$ is equivalent to \begin{array}{l}\require{cancel} F-32=\dfrac{9}{5}C \\\\ 5(F-32)=9C \\\\ \dfrac{5(F-32)}{9}=C \\\\ C=\dfrac{5(F-32)}{9} .\end{array}
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