Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 2 - Test: 3


The statement is false. No solution.

Work Step by Step

Solve this equation: 3(y-4)+y=2(6+2y) 3(y-4)+y=2(6+2y) Distribute the 3 and the 2. 3y-12+y=12+4y Combine like terms. 4y-12=12+4y Subtract 4y from both sides. -12$\ne$12 No Solution.
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