## Intermediate Algebra (6th Edition)

$(-2,5)$
$|2x-3| \lt 7$ This is equivalent to $-7 \lt 2x-3 \lt 7$ Using inequality properties, add $3$ to all three parts. $-7+3 \lt 2x-3+3 \lt 7+3$ $-4 \lt 2x \lt 10$ Divide all parts by $2$ $\frac{-4}{2} \lt \frac{2x}{2} \lt \frac{10}{2}$ $-2 \lt x \lt 5$ In Interval Notation: $(-2,5)$