Chapter 2 - Section 2.7 - Absolute Value Inequalities - Exercise Set - Page 106: 88

$P(\text{rolling a }1,2,3,4,5\text{ or } 6)=1$

Rolling a 1, 2, 3, 4, 5, or 6 is all the possible outcomes of rolling a die. Hence the probability of rolling a 1, 2, 3, 4, 5, or 6 is \begin{array}{l}\require{cancel} P(\text{rolling a }1,2,3,4,5\text{ or } 6)=\dfrac{6}{6} \\\\ P(\text{rolling a }1,2,3,4,5\text{ or } 6)=1 .\end{array}